calculate the density of a gold ring that has a mass of 15.83 grams and a volume of 0.82 milliliters. What is the density of the gold ring. (The formula for density is Density= Mass/Volume)

6 answers

To calculate the density of the gold ring, you can use the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given:

  • Mass = 15.83 grams
  • Volume = 0.82 milliliters

Now, plug these values into the formula:

\[ \text{Density} = \frac{15.83 , \text{grams}}{0.82 , \text{milliliters}} \approx 19.29 , \text{grams/milliliter} \]

Therefore, the density of the gold ring is approximately 19.29 grams/milliliter.

Now, calculate the density of a gold bar that has a mass of 1,000 grams and a volume of 51.8 milliliters. Use the same formula for density.

To calculate the density of the gold bar, you can use the same formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given:

  • Mass = 1,000 grams
  • Volume = 51.8 milliliters

Now, plug these values into the formula:

\[ \text{Density} = \frac{1000 , \text{grams}}{51.8 , \text{milliliters}} \approx 19.31 , \text{grams/milliliter} \]

Therefore, the density of the gold bar is approximately 19.31 grams/milliliter.

Which equation describes the mass of an object in relation to its volume and density?(1 point)
Responses

m=D×V
m=D×V

m=D+V
m is equal to cap d plus cap v

m=DV
m is equal to cap d over cap v

m=VD

The correct equation that describes the mass of an object in relation to its volume and density is:

\[ m = D \times V \]

So, the response is:

m = D × V

Now, calculate the density of a gold bar that has a mass of 1,000 grams and a volume of 51.8 milliliters. Use the same formula for density.