Calculate the change in temperature that would shrink a room-temperature balloon to one-half its size. Vo is 10 Vf is 5
4 answers
room temp is 20 C right?
P V = n R T
V and T change
P stays constant - 1 atmosphere
n stays constant, same molecules in there
R just plain is a constant
so
T = constant * V
V2 = .5 V1
T1 = constant * V1
T2 = constant * .5 V1 = constant * .5 T1
half the volume is half the temperature
if the original temp was 20 C that is 293 K
so the final temp is 146 K or -127 C
V and T change
P stays constant - 1 atmosphere
n stays constant, same molecules in there
R just plain is a constant
so
T = constant * V
V2 = .5 V1
T1 = constant * V1
T2 = constant * .5 V1 = constant * .5 T1
half the volume is half the temperature
if the original temp was 20 C that is 293 K
so the final temp is 146 K or -127 C
okay ... 20ºC ... or 293ºK
gas volume is proportional to the absolute (Kelvin) temperature
so half of the ambient temperature is the change required
gas volume is proportional to the absolute (Kelvin) temperature
so half of the ambient temperature is the change required
so using Charles' law