Asked by mel
calculate the change in energy expected for each of the following processes
1. Rb(g) + Br(g) --> Rb+ (g) + Br- (g)
2. Mg(g) + I(g) --> Mg+ (g) + I- (g)
3. Mg+ (g) + I(g) -> Mg+2 (g) + I- (g)
4. Mg(g) + 2I (g) -> Mg+2 (g) + 2I- (g)
in kJ
1. Rb(g) + Br(g) --> Rb+ (g) + Br- (g)
2. Mg(g) + I(g) --> Mg+ (g) + I- (g)
3. Mg+ (g) + I(g) -> Mg+2 (g) + I- (g)
4. Mg(g) + 2I (g) -> Mg+2 (g) + 2I- (g)
in kJ
Answers
Answered by
DrBob222
For #1, you want the to add the two following:
Rb(g) ==> Rb^+(gas) + e I.P. (Ionization potential). This will be a positive number.
Br(g)+ e =>Br^-(g) +E.A. (electron affinity) This will be a negative number.
The others are done the same way. In the case of #2, you are removing only 1 electron from Mg(g); therefore, you want only I.P. #1 and not #2.
Rb(g) ==> Rb^+(gas) + e I.P. (Ionization potential). This will be a positive number.
Br(g)+ e =>Br^-(g) +E.A. (electron affinity) This will be a negative number.
The others are done the same way. In the case of #2, you are removing only 1 electron from Mg(g); therefore, you want only I.P. #1 and not #2.
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