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Calculate the change in energy of an atom that emits a photon of wavelength 2.21 meters. (Planck’s constant is 6.626 x 10-34 joule seconds, the speed of light is 2.998 x 108 m/s)
10 years ago

Answers

Damon
h f
where h = 6.626 * 10^-34
f = 1/T = c/lambda = 2.998*10^8/2.21

so
E = 6.626*10^-34 * 2.998*10^8/2.21 Joules
10 years ago
Anonymous
dont
7 years ago

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