q = mass ice x dHfusion.
w = -p*delta V.
Calculate volume ice at zero C. I would look up the density of ice at zero C and liquid H2O at 0C, then solve for volume for 18.015g ice and water. I found that here of (0.9167 g/cc for ice @ 0C vs 0.9998 @ 0Cg/cc for liquid water).
http://en.wikipedia.org/wiki/Ice
That will give you delta V from which you can solve for w (in L*atm). Multiply by 101.325 to change to Joules.
Then E = q + w.
NOTE: The volume of ice is greater than the volume of liquid water. Watch the sign.
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