Asked by Monique
an 8.5g ice cube is placed into 255g of water. Calculate the temp change in the water upon the complete melting of the ice. Hint: Determine how much heat is absorbed by the melting ice and then use q = mc^T to calculate the temp change of the 255g of water
Answers
Answered by
DrBob222
q1 = heat to melt 8.5 g ice.
q1 = mass ice x heat fusion.
q2 = heat to raise T melted ice to Tfinal
q2 = mass melted ice x specific heat water x (Tfinal-Tintial)
q3 = heat lost by 255 g H2O
q3 = mass water x specific heat water x (Tfinal-Tinitial)
q1 + q2 + q3 = 0
Solve for Tfinal.
q1 = mass ice x heat fusion.
q2 = heat to raise T melted ice to Tfinal
q2 = mass melted ice x specific heat water x (Tfinal-Tintial)
q3 = heat lost by 255 g H2O
q3 = mass water x specific heat water x (Tfinal-Tinitial)
q1 + q2 + q3 = 0
Solve for Tfinal.
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