Calculate (in calories) the amount of heat needed to melt 96g of ice at -24 degrees C to water at 28 degrees C.

Answer 1

You need two equations.
1. Within a phase
q = mass x specific heat x (Tfinal-Tinitial). For example, for warming from zero C to 28 C you will have
q = mass x specific heat x (28-0) = ?

2. At the phase change. For example, at the melting point you have
q = mass x heat fusion

So you will have q from -24 to zero, at zero, and from zero to 28. Then add each for the total.