HClO4 is a strong acid meaning that it ionizes 100%; therefore,
HClO4 ==> H^+ + ClO4^-
0.170.....0.......0
-0.170...0.170..0.170
...0.....0.170...0.170
This gives the (H^+) [which is the same as H3O^+].
You can obtain OH by
(H^+)(OH^-) = Kw = 1E-14.
Calculate [H3O ], [ClO4–], and [OH–] in an aqueous solution that is 0.170 M in HClO4(aq) at 25 °C.
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