Calculate each of the following quantities:
(a) Grams of solute in 185.8 mL of 0.267 M calcium acetate 7.85g Ca(C2H3O2)2
(b) Molarity of 500. mL of solution containing 21.1g of potassium iodine 0.254 M KI
(c) Moles of solute in 145.6 L of 0.850 M sodium cyanide 124 mol NaCN
1 answer
Those answers look good to me. Good work.