Calculate delta H for this reaction:

Question

N2 + 3H2 --> 2NH3

I am given the bond dissociation energy for N-N (163 kJ/mol), H-H (436 kJ/mol), and N-H (391 kJ/mol)

I can't seem to find a similar problem anywhere, they are all given 2 or 3 similar equations.

Answer 1

dHrxn = (n*BE reactants) - (n*BE products)

Answer 2

thanks!