calculate cell potential at 25C for:

3Fe3+(aq) + AL(s)= 3Fe2+(aq)+ Al3+ (aq)

if Fe3+ = 0.300 M, Fe2+ = 0.150M
Al3+ = 0.300M. The standard reduction potentials are as follows:
Fe3+ (aq) + e- = Fe2+ (aq)
Al3+ (aq) + 3e-=Al (s)
Eo = +0.771 V
Eo = -1.66 V

1 answer

Fe^+3 + e ==> Fe^+2 Eo = +0.771 v
Al==> Al^+3 + 3e Eo = +1.66 v
Ecell = .771 + 1.66 = ??
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