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Calculate the emf of the cell

CR|Cr3+(0.1M)||Fe2+(0.1M)Fe
Given, E°Cr3+|CR = -0.75v
E°Fe2+|Fe = -0.45v
Cell reactn 2Cr(s)+3Fe2+(aq) -> 2Cr3+(aq)+3Fe(s)

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Ecell=Ecathode-Eanode
=-0.44+0.74
=0.30V

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