To calculate the number of bond pairs in xenon tetrafluoride (XeF4), we must first understand its molecular structure.
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Lewis Structure: Xenon (Xe) is the central atom, and it is surrounded by four fluorine (F) atoms. Each fluorine atom forms a single bond with the xenon atom.
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Bond Pairs: In the molecular structure of XeF4, there are four single bonds between xenon and each fluorine atom. Therefore, there are four bond pairs.
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Lone Pairs: Additionally, xenon has a total of 8 valence electrons (as a noble gas) and it uses 4 of them to bond with the four fluorine atoms. This leaves 4 remaining electrons, which are typically arranged as 2 lone pairs on the xenon atom.
In summary, XeF4 has four bond pairs formed by the four Xe-F bonds, and these are arranged in a square planar geometry due to the presence of the lone pairs.
So, the answer is:
Number of bond pairs in XeF4: 4.