Ptotal = pH2O + pCO2
Ptotal = 1.87 atm x (760 mm/1 atm) = 1421.2 mm
1421.2 mm = 18.7 mm + pCO2
Solve for pCO2. That is the pressure in mm for the dry gas.
Then PV = nRT
You know PCO2, V = 0.278 L; n = ?; R = you know; T = 273 + 21 = 294
Solve for n = mols CO2
Then mols CO2 x molar mass CO2 = grams CO2.
Post your work if you get stuck or have questions.
Calcium carbonate is heated in a test tube and it decomposes to produce CO2 that is collected over water in the following setup. The volume of the gas that is collected is 0.278 L and the total pressure in the collection tube is 1.87 atm at 21 degrees C. The vapor pressure of the water at 21 degrees C is 18.7 tor. What mass of CO2 was collected in the collection tube?
2 answers
Okay this is what I did initially but I was not too sure of it. Thank you very much
2 answers