dHrxn = (n*dHf products) - (n*dHf products)
dHrxn = -127 = (n*dHf .....etc)
Substitute and solve for dHf CaC2 which is the only unknown in the equation.
Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) gas and calcium hydroxide (Ca(OH)2). If the ΔH for:
CaC2(s) + 2H2O(l) = Ca(OH)2(s) + C2H2(g)
is -127 kJ, then what is the enthalpy of formation for calcium carbide? The ΔH of formation for H2O(l), Ca(OH)2(s) and C2H2(g) are -286, -986, 227 kJ/mol respectively. The units are kJ.
1 answer
1 answer