​CaCO3→CO2​+CaO

Question

A scientist heats 30 grams of calcium carbonate (CaCO3
) in the chemical reaction shown. What is the total mass of the products?

Answer 1

To find the total mass of the products, we need to determine the molar mass of each compound involved in the reaction.

The molar mass of CaCO3 (calcium carbonate) is:
1 calcium (Ca) atom with a molar mass of 40.08 g/mol
1 carbon (C) atom with a molar mass of 12.01 g/mol
3 oxygen (O) atoms with a molar mass of 16.00 g/mol each

Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (16.00 g/mol x 3) = 100.09 g/mol

According to the balanced chemical equation, 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO. Therefore, the molar mass of the products can be calculated as follows:

Molar mass of CO2 = 12.01 g/mol + (16.00 g/mol x 2) = 44.01 g/mol

Molar mass of CaO = 40.08 g/mol + 16.00 g/mol = 56.08 g/mol

Now, we need to find the number of moles of CaCO3 in 30 grams:

Number of moles = Mass / Molar mass
Number of moles of CaCO3 = 30 g / 100.09 g/mol = 0.2996 mol (approx.)

Since the molar ratio of CaCO3 to CO2 and CaO is 1:1, the number of moles of CO2 and CaO produced will also be 0.2996 mol each.

To find the mass of each product, we can multiply the number of moles by their respective molar masses:

Mass of CO2 = 0.2996 mol x 44.01 g/mol = 13.2 g (approx.)
Mass of CaO = 0.2996 mol x 56.08 g/mol = 16.8 g (approx.)

Therefore, the total mass of the products is approximately 13.2 g + 16.8 g = 30 g.