To find the total mass of the products, we need to figure out the molar masses of CO2 and CaO.
The molar mass of CO2 is 12.01 g/mol (for C) + 16.00 g/mol (for each O) = 44.01 g/mol.
The molar mass of CaO is 40.08 g/mol (for Ca) + 16.00 g/mol (for O) = 56.08 g/mol.
Since the molar mass of CaCO3 is 40.08 g/mol (for Ca) + 12.01 g/mol (for C) + (16.00 g/mol for each O) = 100.09 g/mol.
We know that the molar mass of CaCO3 is 100.09 g/mol and the molar mass of CO2 is 44.01 g/mol. This means that for every 100.09 g of CaCO3 heated, 44.01 g of CO2 is produced.
Therefore, if 30 g of CaCO3 is heated, the mass of CO2 produced will be (30g / 100.09g/mol) * 44.01g/mol = 13.2 g.
Since the reaction also produces CaO, with a molar mass of 56.08 g/mol, the total mass of the products will be 13.2 g (for CO2) + (30 g / 100.09 g/mol) * 56.08 g/mol = 13.2 g + 16.8 g = 30 g.
So, the total mass of the products in this reaction is 30 grams.
A scientist heats 30 grams of calcium carbonate(CaCO3) in the chemical reaction shown. What is the total mass of the products. CaCO3 - CO2 + CaO
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