Ca = 40 g/mol
N = 14 g/mol
3 Ca = 120 g/mol of Ca3N2
2 N = 28 g/mol of Ca3N2
so we need 28 g N for every 120 g of Ca
so yes, if you have 50 g of each, then Ca is the limiting reagent
I only need 50 *28/120 = 21 grams of N so
50 -21 = 29 would be left over
Ca3N2 molar mass = 120 + 28 = 148 g/mol
148/120 * 50 = 61.7 g of Ca3N2 I get
Ca+N-->Ca3N2
-What is limiting reagent?
-Mass of calcium nitride formed when 50.0g of calcium reacts with 50.0g of Nitrogen?
-Excess?
CAN SOMEONE DOUBLE CHECK MY ANSWERS:
Calcium is limiting reagent.
Mass of Ca3N2: 68.4g Ca3N2
Excess: 38.4N left over.
2 answers
Awesome that's what I got too.
6 answers