c^2 - 4c = 12
c^2 - 4 + 4 = 12 + 4
(c-2)^2 = 16
c-2 = ±4
c = 6 or c = -2
c squared-4c-12=0
we have to solve each equation by completing the square.
3 answers
when you added 4 on your second step, your 'c' dissapeared... where'd it go?
typo error, it should be there as 4c
If you expand (x-2)^2 you will see I did not lose it.
If you expand (x-2)^2 you will see I did not lose it.
0 answers