By what mass (in grams) will a chromium cathode increase when it is coupled to a magnesium half cell in which the magnesium anode loses 1.53 grams? (assuming chromium ions in solution are Cr^3+).

Answer 1

96,500 C will deposit 24.3/2 = 12.15 g Mg metal.

96, 500 C will deposit 52/3 = 17.33 g Cr

1.53 g Mg loss x (17.33/12.15) = 2.182 is the shortcut way to solve this. I can show you the long way if you want to see it. Actually, the long way is easier to undestand, I think.

Answer 2

I would greatly appreciate it if you could show me the long way walkthrough. Thank you!