I tried something for this. could you please check?
Limiting reagent is Cr because O2 is unlimited.
For every 4 moles of Cr, there's 3 moles of O2.
38.5molesCr (3molesO2 / 4molesCr) = 28.9 moles O2.
Molar Mass of O2 is 32 so 1moleO2 = 32gO2.
28.9molesO2 (32gO2 / 1moleO2) = 924gO2.
38.5molesCr (52gCr / 1moleCr) = 2002gCr
Mass of Cr2(O2)3 is 924 + 2002 = 2926.
I don't know if I answered the last question and I don't know if this is right. Please let me know. Thanks!
Determine the type of chemical reaction, find the limiting reagent, determine the amount of product in grams, and the amount of grams of excess reagent.
Chromium metal is heated with oxygen to give chromium (III) oxide. Start with 38.5 moles chromium metal and unlimited oxygen gas.
The equation is 4Cr(s) + 3O2(g) --> 2Cr2(O2)3(s) and it is a synthesis reaction. I am not sure how to figure out the rest.
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