NaOH + HCl ==> NaCl + H2O
mols NaOH = M x L = ?
mols HCL = mols NaOH since 1 mol NaOH reacts with 1 mols NaOH.
Then M HCl = mols HCl/L HCl = ?
By titration it is found that 12.1 mL of 0.130 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.
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