2C4H10(g)+13O2(g)→8CO2(g)+10H2O(l)
mols butane = grams/molar mass
Using the coefficients in the balanced equation, convert mols butane to mols CO2.
Now use PV = nRT and solve for V in liters. n = number of mols calculated in step 2.
Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(l)
At 1.00 atm and 23 ∘C, what is the volume of carbon dioxide formed by the combustion of 3.20g of butane?
1 answer
1 answer