brewery's filling machine is adjusted to fill bottles with a mean of 33.8 oz. of ale and a variance of 0.004. Periodically, a bottle is checked and the amount of ale noted.

Question

brewery's filling machine is adjusted to fill bottles with a mean of 33.8 oz. of ale and a variance of 0.004. Periodically, a bottle is checked and the amount of ale noted.
(a) Assuming the amount of fill is normally distributed, what is the probability that the next randomly checked bottle contains more than 33.88 oz?

I tried to plug in the info and square the variance. i have the Z Chart, but I am lost.

PsyDAG · Answer

Z = (score-mean)/SD = (33.88-33.8)/SD SD =√variance