bearing 40degree
distance 46km
brenda walks 7km for a bearing of 120degrees then 9km for a bearing of 180degrees.Calculate distance and and bearing?
3 answers
the bearing has to be between 120º and 180º
she walked 16 km total , so the distance must be less than that
40º and 46 km makes no sense
use N/S and E/W components of each segment of the trip to find the total resultant
she walked 16 km total , so the distance must be less than that
40º and 46 km makes no sense
use N/S and E/W components of each segment of the trip to find the total resultant
D = 7km[120o] + 9km[180o].
X = 7*sin120 + 9*sin180 = 6.06 km.
Y = 7*Cos120 * 9*Cos180 = -12.5 km.
D = 6.06 - 12.5i = 13.9km[-25.9o] = 13.9km[25.9o] S. of E. = 13.9km[103.5o] CW(bearing).
Tan A = X/Y.
X = 7*sin120 + 9*sin180 = 6.06 km.
Y = 7*Cos120 * 9*Cos180 = -12.5 km.
D = 6.06 - 12.5i = 13.9km[-25.9o] = 13.9km[25.9o] S. of E. = 13.9km[103.5o] CW(bearing).
Tan A = X/Y.
2 answers