Asked by Rashidat
A girl walks 7km on a bearing of 030° she then changes direction and walks 8km on a bearing of 120° find the distance and bearing from her starting point
Answers
Answered by
Rashidat
Pls solve it
Answered by
mathhelper
Did you make a diagram of the triangle?
I have mine showing sides of 7 and 8 with a 90° angle between them.
So it is just using Pythagoras
d^2 = 7^2 + 8^2 = 113
d = √113 = appr 10.63 km
For the angle of the triangle at the starting point:
tanθ = 8/7 = ....
θ = appr 48.8°
bearing from start = 48.8 + 30° = 78.8°
I have mine showing sides of 7 and 8 with a 90° angle between them.
So it is just using Pythagoras
d^2 = 7^2 + 8^2 = 113
d = √113 = appr 10.63 km
For the angle of the triangle at the starting point:
tanθ = 8/7 = ....
θ = appr 48.8°
bearing from start = 48.8 + 30° = 78.8°
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