Br2 + 5F2 --> 2BrF5

How many molecules Br2 react with 1.11 x 10^20 molecules F2?

I got 2.21 x 10^47 but I feel that's too big and is most likely wrong. Can someone help me?

5 answers

i redid my work and got 2.21 x 10^19 molecules Br2. I don't know if that's right either, it seems a tad high.

This factor is no different than whn you work stoichiometry problems.
1.11E20 x (1 mole Br2/5 mols F2) = ??

2.22 x 10^19 molecules Br2

yes

Thank you DrBob222

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