The balanced equation for the reaction is:
N2(g) + 3H2(g) -> 2NH3(g)
From the equation, we can see that 1 molecule of N2 reacts with 3 molecules of H2 to produce 2 molecules of NH3.
Given:
25 N2 molecules react with 60 H2 molecules.
We need to determine which molecules are completely consumed.
For every 1 molecule of N2, we need 3 molecules of H2. Therefore, the maximum number of N2 molecules that can react is 25.
Since we have 60 H2 molecules, we have more than enough to react with the available N2 molecules. Therefore, the H2 molecules are in excess and will not be completely consumed.
To find the number of NH3 molecules formed, we need to calculate the number of N2 molecules that react.
Since 1 molecule of N2 reacts with 3 molecules of H2 to form 2 molecules of NH3, the number of NH3 molecules formed will be half of the number of N2 molecules that react.
Therefore, the number of NH3 molecules formed = (25 N2 molecules / 2) = 12.5 NH3 molecules
However, we cannot have a fraction of a molecule, so we round down to the nearest whole number.
The number of NH3 molecules formed = 12 NH3 molecules.
In summary:
- The H2 molecules will be in excess and not be completely consumed.
- 12 NH3 molecules are formed.
Ammonia is produced from reaction with hydrogen according to equation: N(g)+3H (g)2NH (g). If 25 N; molecules react with 60 H molecules in a sealed container, which molecules will be completely consumed? How many NH, molecules are formed? Ans: H; 40 NH, molecules).
Ammonia is produced in the following reaction: N (g)+3H (g) 2NH
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