1. V^2 = Vo^2 + 2g*h = 0 + 19.6*50 =
V = ?
2. 0.5g*t^2 = 50.
4.9t^2 = 50,
3. F = M*g = 2 * 9.8 =
body of mass 2kg falls freely from rest through a height of 50m and comes to rest having penetrated 5.0cm of sand.
Calculate.
(I) The velocity with which the ball hits the sand.
(II) The time taken in falling.
(III) The average force exerted by the sand in bringing the body to rest.
1
2 answers
3. No, the average force is the change in momentum divided by the time to stop m V / tstop
where tstop is the stopping time
(1/2) V tstop = 0.05 meters
where tstop is the stopping time
(1/2) V tstop = 0.05 meters
4 answers