heat=mass*specht*deltaT
deltatempB=heat/massb*specificheatB
deltatempB=6heat/massA*specifheatA=6deltTa
Body A has twice the mass and three times the specific heat of body B. They are supplied with equal amounts of heat. Body A experiences a temperature change ΔT. What change in temperature is experienced by body B?
Question 2 options:
A) ΔT
B) 3ΔT/2
C) 2ΔT/3
D) 6ΔT
E) ΔT/2
3 answers
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