The latent heat of vaporization of H2O at body temperature (37°C) is 2.42 x 106 J/kg. To cool the body of a 77.6-kg jogger [average specific heat capacity = 3500 J/(kg C°)] by 2.78 C°, how many kilograms of water in the form of sweat have to be evaporated?

Answer 1

(77.6)(3500)(2.78)=M(2.42E^6)
755048=M(2.42E^6)
M=0.312