Asked by Mischa
Boats A and B leave the same place at the same time. Boat A heads due North at 12 km/hr. Boat B heads due East at 18 km/hr. After 2.5 hours, how fast is the distance between the boats increasing?
You are looking at a right-angled triangle, let S be the distance between them
Then S^2 = (12t)^2+(18t)^2=468t^2
then 2S dS/dt = 936t when t-2.5, S = 2925 km
So dS/dt = 936(2.5)/(2x2925) = 0.4 km/h
Actually i figured it. But the correct answer is 21.63 km/hr. Thanks anyways.
of course Mischa, you are right, it looks like I did not take the square root of my S.
Good for you for being alert.
You are looking at a right-angled triangle, let S be the distance between them
Then S^2 = (12t)^2+(18t)^2=468t^2
then 2S dS/dt = 936t when t-2.5, S = 2925 km
So dS/dt = 936(2.5)/(2x2925) = 0.4 km/h
Actually i figured it. But the correct answer is 21.63 km/hr. Thanks anyways.
of course Mischa, you are right, it looks like I did not take the square root of my S.
Good for you for being alert.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.