To find the area of a circle, you use the formula A = πr^2, where A is the area and r is the radius.
For the training wheel:
A_training = π(3)^2
A_training = 9π
For the regular bicycle wheel:
A_regular = π(10)^2
A_regular = 100π
Next, subtract the area of the training wheel from the area of the regular wheel:
A_regular - A_training = 100π - 9π
A_regular - A_training = 91π
Now, calculate the numerical value of 91π:
A_regular - A_training = 91 * 3.14159
A_regular - A_training ≈ 285.61
Therefore, the area of the training wheel is approximately 285.61 square inches smaller than the area of the regular bicycle wheel.
bicycle training wheel has a radius of 3 inches. A regular
bicycle wheel has a radius of 10 inches. Approximately how much smaller, in square inches and rounded to the nearest hundredth, is the area of the training
wheel than the area of the regular bicycle wheel?
5 answers
Wrong
My apologies for the mistake. Let's correct that.
Area of the training wheel:
A_training = π(3)^2
A_training = 9π square inches
Area of the regular bicycle wheel:
A_regular = π(10)^2
A_regular = 100π square inches
Now, calculate the difference in area:
Difference = A_regular - A_training
Difference = 100π - 9π
Difference = 91π square inches
To find the numerical value of the difference:
Difference ≈ 91 * 3.14159
Difference ≈ 285.97 square inches
Therefore, the area of the training wheel is approximately 285.97 square inches smaller than the area of the regular bicycle wheel.
Area of the training wheel:
A_training = π(3)^2
A_training = 9π square inches
Area of the regular bicycle wheel:
A_regular = π(10)^2
A_regular = 100π square inches
Now, calculate the difference in area:
Difference = A_regular - A_training
Difference = 100π - 9π
Difference = 91π square inches
To find the numerical value of the difference:
Difference ≈ 91 * 3.14159
Difference ≈ 285.97 square inches
Therefore, the area of the training wheel is approximately 285.97 square inches smaller than the area of the regular bicycle wheel.
Are u sure
I apologize for the incorrect calculations in my previous responses. Let's double-check the calculations now:
Area of the training wheel:
A_training = π(3)^2
A_training = 9π square inches
Area of the regular bicycle wheel:
A_regular = π(10)^2
A_regular = 100π square inches
Now, calculate the difference in area:
Difference = A_regular - A_training
Difference = 100π - 9π
Difference = 91π square inches
To find the numerical value of the difference:
Difference ≈ 91 * 3.14159
Difference ≈ 285.61 square inches
Therefore, after recalculating, the correct answer is that the area of the training wheel is approximately 285.61 square inches smaller than the area of the regular bicycle wheel. Thank you for your patience.
Area of the training wheel:
A_training = π(3)^2
A_training = 9π square inches
Area of the regular bicycle wheel:
A_regular = π(10)^2
A_regular = 100π square inches
Now, calculate the difference in area:
Difference = A_regular - A_training
Difference = 100π - 9π
Difference = 91π square inches
To find the numerical value of the difference:
Difference ≈ 91 * 3.14159
Difference ≈ 285.61 square inches
Therefore, after recalculating, the correct answer is that the area of the training wheel is approximately 285.61 square inches smaller than the area of the regular bicycle wheel. Thank you for your patience.
2 answers