To solve this problem, we first need to identify the two forces acting in the horizontal direction that will give a net force of 300 N to the right.
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Label the Two Forces:
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Let's denote the force exerted by the left Sumo wrestler on the right as \( F_{\text{left}} \) and the force exerted by the right Sumo wrestler on the left as \( F_{\text{right}} \).
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In order to have a net force of 300 N to the right, we can set up the equation:
\[ F_{\text{net}} = F_{\text{left}} - F_{\text{right}} = 300 , \text{N} \]
To specify values, we could say:
- \( F_{\text{left}} = 600 , \text{N} \) (force exerted to the right)
- \( F_{\text{right}} = 300 , \text{N} \) (force exerted to the left)
Thus, dragging and dropping, we label:
- Force 1: \( F_{\text{left}} = 600 , \text{N} \) to the right
- Force 2: \( F_{\text{right}} = 300 , \text{N} \) to the left.
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Calculate the Acceleration of the Flying Sumo Wrestler:
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The net force acting on the right Sumo wrestler is given as 300 N to the right. Using Newton's second law \( F = ma \):
\[ F_{\text{net}} = m \cdot a \Rightarrow a = \frac{F_{\text{net}}}{m} \]
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Plugging in the values:
\[ a = \frac{300 , \text{N}}{150 , \text{kg}} = 2 , \text{m/s}^2 \]
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So in summary:
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Label the forces:
- \( F_{\text{left}} = 600 , \text{N} \) to the right
- \( F_{\text{right}} = 300 , \text{N} \) to the left
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Label the acceleration:
- Acceleration of the flying Sumo Wrestler: \( 2 , \text{m/s}^2 \) to the right.