Below is a simplified force diagram representing two Sumo wrestlers attempting to push each other out of the ring. Note that the box in the middle is there to help you visualize.

1. Use the boxes at the top to drag and drop. Label the 2 forces acting in the horizontal direction so that the Net Force is equal to 300 N to the right (Direction matters here).
2. Assume that once the Sumo wrestler (mass = 150 kg) on the right goes flying with the Net Force from step 1. Label the last box at the bottom with the correct acceleration for the flying Sumo Wrestler. (Assume to the right is the positive direction). Hint: Use the equation for Force F=ma to solve.

1 answer

Let's break down the problem step by step.

Step 1: Labeling the Forces

To have a Net Force of 300 N to the right, we can assume that one wrestler is exerting a force to the right, and the other wrestler is exerting a force to the left.

Let's denote the forces as follows:

  • Force exerted by the wrestler on the right (F_right): +300 N (to the right)
  • Force exerted by the wrestler on the left (F_left): -0 N (since 300 N to the right indicates that the left wrestler isn't exerting enough force to counteract it effectively).

So, when you fill in the boxes for the forces acting in the horizontal direction, it would look like this:

  • F_right = 300 N (to the right)
  • F_left = 0 N (no opposition mentioned)

Step 2: Calculating the Acceleration

Now we need to find the acceleration of the wrestler on the right. We can use Newton's second law, which states:

\[ F_{net} = m \cdot a \]

Where:

  • \( F_{net} = 300 , N \) (the net force acting on the 150 kg wrestler)
  • \( m = 150 , kg \) (the mass of the wrestler)
  • \( a \) is the acceleration we need to find.

Rearranging the equation for acceleration:

\[ a = \frac{F_{net}}{m} \]

Substituting the values:

\[ a = \frac{300 , N}{150 , kg} \] \[ a = 2 , m/s^2 \]

Conclusion

The final answers for the labels would be:

  1. Forces acting in the horizontal direction:

    • F_right = 300 N (to the right)
    • F_left = 0 N (no opposing force)
  2. The acceleration of the flying Sumo wrestler:

    • Acceleration = 2 m/s² (to the right)

This correctly represents the scenario as specified in your question.