v = 80 - 32t
v = 0 is where the ball stops rising and starts falling
0 = 80 - 32t
t = 2.5s
h = 96 + 80t - 16t^2
= 96 + 80*2.5 - 16*6.25
= 196 ft
ball thrown up from top of 96 foot high tower with initial velocity of 80 ft/s.
when does ball reach max height and how high is it at that time?
2 answers
what is the -32 t? I think I undersaand the rest.