Balance these reactions using the half-reaction method
Sn2+ + IO3- -> Sn4= + I- (acidic solution)
CrO2 + ClO- -> CrO42- + Cl- (basic solution)
2 answers
Sn2+ +io3- = sn4- + i-
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Sn2+ + IO3- -> Sn4= + I- (acidic solution)
CrO2 + ClO- -> CrO42- + Cl- (basic solution)
2 answers