Balance the following in basic solution: Al(s) + CrO42¯(aq) → Al(OH)3(s) + Cr(OH)4¯(aq)

Question

Can someone please help me do this. I having a hard time, especially determining the charge of Al(OH)3. Thanks to anyone who helps

Answer 1

The charge of Al(OH)3 is zero as is the charge of all compounds.
In the equation Al has changed from an oxidation state of zero to an oxidation state of +3 in Al(OH)3.