Balance the equation in aqueous basic solution:
Fe(CN)64-(aq) + Ce4+(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
1 answer
Again you need to check you have the correct equation as you have O atoms on the RHS but none on the LHS.
Fe(CN)64-(aq) + Ce4+(aq) → Ce3+(aq) + Fe3+(aq) + CO32-(aq) + NO3-(aq)
1 answer