50 * (1/2)^n = 1 ???
.5^n = .02
n ln .5 = ln .02 (any base log will do)
n = ln(.02) / ln(.5)
then n * 283.2
Ba has a half-life of 283.2 hours. How long would it take for the 50 mg of Ba in a sample to decay to 1.0 mg?
4 answers
isnt it..
1=50(.5)^(x/283.2)
1/50=(.5)^(x/283.2)
logbase.5(1/50)=x/283.2
x=1598.34
1=50(.5)^(x/283.2)
1/50=(.5)^(x/283.2)
logbase.5(1/50)=x/283.2
x=1598.34
s=k ln W * / g!^¥ + ([x:86:23]<€{fn t})
what does this means?
what does this means?
It means you are trying to win the lotto from a useless formula that some blokes made up to have a fun time... Fun time of what you ask? Fun time at laughing at alllll the people who believe this BS...