(b^(-4y+7))(b^y) / b

I got 1 / b^(3y-8)

but the answer is supposed to be 1 / b^(3y+6) ?

could someone write the steps to solving this?

3 answers

I just solved it and i know how to get 1 / b^(3y+6) as the answer

but, if for the exponent -4y+7 if it isn't -(4y+7) I wouldn't move it to the bottom of a fraction?
by answer I meant b^-3y+6
You may put the exponents in the numerator or denominator.

a3= 1/a-3

sometimes teachers have beginning students move them around just for practice.