As written, you have
ax + b/cx + d = 2
acx^2 + (d-2)cx + b = 0
x = [c(2-d)±√((c(d-2))^2-4abc)]/2ac
I assume you meant
(ax+b)/(cx+d)=2
2(ax+b) = (cx+d)
2ax + 2b = cx + d
(2a-c)x = d-2b
x = (d-2b)/(2a-c)
ax+b/cx+d=2
solve for x
1 answer