Average rate of change:
h(x)= x^3 -0.5e^x at [0,1]
2 answers
The 1/2 should be 1/3, sorry
If you mean that the 0.5 should be 1/3, then
h(x) = x^3 - 1/3 e^x
h(0) = -1/3
h(1) = 1 - e/3
so, avg rate of change is (h(1)-h(0))/(1-0) = 4/3 - e/3
h(x) = x^3 - 1/3 e^x
h(0) = -1/3
h(1) = 1 - e/3
so, avg rate of change is (h(1)-h(0))/(1-0) = 4/3 - e/3
1 answer