At what pressure would 0.150 mole of nitrogen gas at -23.0^o C occupy 8.90 L ?

Answer 1

P=nRT/V

change temp to kelvins

Answer 2

thanks bob

Answer 3

P = nRT / V

P = [ (0.150 mol) (0.08206 L atm mol¯1 K¯1) (296.0 K) ] / 8.90 L