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How many moles of helium occupy 26.4 L at a pressure of 103.0 kPa, and 10 degrees Celsius?
A.) 0.03 mole
B.) 0.86 mole
C.) 1.16 mole
D.) 32.72 mole

1 answer

PV = nRT

P = pressue
V = volume
n = moles
R = 8.31
T = Temperature (0c = 273K)

(103.0)(26.4) = n(8.31)(283)
2719.2 = n(2351.73)
2719.2 / 2351.73 = n
m = 1.16

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