At what angle to the x-axis does the graph of y=sin x pass through (0,0)? Give numerical and visual evidence.
2 answers
Hint: it is zero degrees. PLot it.
The angle would be the same as a tangent to the curve at that point
dy/dx = cosx
at (0,0) , dy/dx = cos0 = 1
dy/dx = 1 = tanØ, where Ø is the angle it makes with the x-axis
tanØ = 1
Ø = 45° or π/4 radians
dy/dx = cosx
at (0,0) , dy/dx = cos0 = 1
dy/dx = 1 = tanØ, where Ø is the angle it makes with the x-axis
tanØ = 1
Ø = 45° or π/4 radians