At the instant oxygen is reacting at the rate 5.0 x 10-4 mol/L*s, at what rate is NO reacting and NO2 forming?
this is a method of initial rate problem. i don't know what to do
the chemical equation is
2 NO(g) + O2 (g) ---> 2 NO2 (g)
3 answers
Both of them have a 2 as a coefficent, so wouldn't the rate be twice that of O2?
i see what your saying. so multiply the rate by two to get the rate of NO? but what is NO2 forming
Won't the rate of disappearance of NO be the same as the rate of formation of NO2 since both of the coefficients are the same?