at the bottom of a loop the speed of an airplane is 400 mph. this causes a normal acceleration of 9 g ft/sec^2, determine the radius of the loop
2 answers
a(norm) = v^2/R
a(normal)=(v^2)÷r
r=(v^2)/a(normal)
r(9 ft/sec^2)(32.17) = (400miles/hr x 1610 m/miles x 3.281 ft/m x (1 hr)/3600)^2
r=1190 ft
r=(v^2)/a(normal)
r(9 ft/sec^2)(32.17) = (400miles/hr x 1610 m/miles x 3.281 ft/m x (1 hr)/3600)^2
r=1190 ft
1 answer