An airplane is flying in a loop, following a circular path with a radius of 2.5 km in the vertical plane. What is the minimum speed that the airplane can maintain without being forced out of the circular path?

Answer 1

To make it over the top the mass times centripetal acceleration must be equal to m g
m g = m v^2/R
9.81 = v^2 / 2500 meters
v^2 = 9.81 * 2500 = 24525
v = 156.6 meters/ second

156.6m/s * (1 km / 1000 meters) * (3600 seconds / hour) = 564 km/hr