At the airport, you pull a 15kg suitcase across the floor with a strap that is at an angle of 45 degrees above the horizontal. Find the normal force and the tension in the strap if the suitcase is pulled at a constant speed and the coefficient of kinetic friction is 0.36.

Answer 1

Ws = M*g = 15 * 9.8 = 147 N. = Wt. of suitcase.

Fn = Ws-T*sin45 = 147 - T*sin45 = 147-0.707T = Normal force.

Fk=u*Fn=0.36*(147-0.707T) = 52.9-0.255T.

T*Cos45-Fk = M*a.
0.707T-(52.9-0.255T) = M*0.
0.707T-52.9+0.255T = 0.
0.961T = 52.9
T = 55 N.

Fn = 147 - 0.707*55 = 108 N.

Answer 2

You pull your 15 kg suitcase at the airport. What is the coefficient of kinetic friction (uk) between the case and the floor if you pull with a force of 50 N, and the suitcase accelerates at 0.52 m/s²

Answer 3

.52